# Line slope calculator x-4y=-11

**Straight line given by points A[1; 3] and B[5; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.25x+2.75

**Canonical form of the line equation:**x-4y+11 = 0

**Parametric form of the line equation:**

x = 4t+1

y = t+3 ; t ∈ R

**Slope:**m = 0.25

**Slope angle of line: φ =**14°2'10″ = 0.245 rad

**X intercept:**x

_{0}= -11

**Y intercept:**y

_{0}= q = 2.75

**Distance line from the origin:**d

_{0}= 2.6679

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; 1)

**Normal vector: n =**(1; -4)

**Midpoint of the segment AB: M =**[3; 3.5]

**Perpendicular Bisector equation:**4x+y-15.5 = 0

**Vector OA = (1; 3) ; |OA| = 3.1623**

**Vector OB = (5; 4) ; |OB| = 6.4031**

**Scalar product OA .OB = 17**

**Angle ∠ AOB = 32°54'19″ = 0.5743 rad**